TREATISE:
. Quantum
Nodal Theory
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Quiz of the Month (October 2004)
Hector C. Parr
SOLUTION TO LAST MONTH'S QUIZ1. 2413 cm2 2. 192 cm 3. 356.2 cm Notes  1. Area of one step = (PI*1042 - PI*402) / 12
2. MA2 = 1042 - 402 (etc.)
3. The PLAN diagram will be identical with that for Q.2.
The ELEVATION shows that the vertical height of B
above A is 15 step thicknesses, i.e. 300 cm.
So AB2 = 3002 + 1922 (etc.)
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THIS MONTH'S QUIZ 1. If AB = 16 cm, BC = 18 cm and CA = 19 cm and A, B and C are the centres of the three circles, find their radii. 2. If DE = 31 cm, EF = 36 cm, FG = 40 cm, GH = 43 cm and HD = 36 cm find the radii of the five circles. 3. If IJ = 1.8 cm, JK = 2.1 cm, KL = 2.1 cm, LM = 2.5 cm and MN = 2.8 cm, find the length of NI. |