TREATISE:
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Nodal Theory
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Quiz of the Month (December 2006)
Hector C. Parr
SOLUTION TO LAST MONTH'S QUIZ
1. 1/6 ft3 2. 1/3 ft3 3. 1.155 ft Notes.  1. Taking EFH as base and A as vertex,
Volume = 1/3 * 1/2 * 1 = 1/6
2. Volume of remainder = 1 - 4 * 1/6 = 1/3
3. AFH is an equilateral triangle with sides sqr(2)
So area AFH = ... = sqr(3)/2
Taking AFH as base and CP as height,
Volume = 1/3 * sqr(3)/2 * CP
So 1/3 = 1/3 * sqr(3)/2 * CP
So CP = 2/sqr(3)
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THIS MONTH'S QUIZ There are seven ways of dividing four people, A, B, C and D,
into two (non-empty) groups, namely:
1. (A) (BCD)
2. (B) (ACD)
3. (C) (ABD)
4. (D) (ABC)
5. (AB) (CD)
6. (AC) (BD)
7. (AD) (BC)
1. In how many ways can five people be divided into two groups?
2. In how many ways can ten people be divided into two groups?
3. In how many ways can ten people be divided into three groups?
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